The area of a rectangular playground is 2,700 ft2. The length is 3
times the width.What are the dimensions of the playground?
L=Lenght
W=Width
A=L*W
L=3W
2700=3W*W
2700=3W^2 Diwide with 3
2700/3=W^2
W^2=900
W=sqroot(900)=30ft
L=3W=3*30=90ft
L=90ft W=30ft
A=L*W=90*30=2700ft^2
To find the dimensions of the playground, we can set up an equation based on the given information. Let's say the width of the playground is 'w' feet.
Given that the length is 3 times the width, we can write the length as 3w feet.
The formula for the area of a rectangle is given by:
Area = Length * Width
Substituting the given values, we have:
2700 ft^2 = (3w) ft * w ft
Now, we can solve this equation to find the value of 'w' (the width).
2700 ft^2 = 3w^2 ft^2
Dividing both sides of the equation by 3, we get:
900 ft^2 = w^2 ft^2
Taking the square root of both sides, we have:
w = sqrt(900) ft
w = 30 ft
Now that we know the width is 30 feet, we can find the length by multiplying it by 3:
Length = 3w = 3 * 30 ft = 90 ft
Therefore, the dimensions of the playground are 90 ft by 30 ft.