a 9v battery is in series with a 10 ohm resistor, a 20 ohm resistor, and a 30 ohm resistor. What is the power absorbed by the 10 ohm resistor?
I want that A 9V battery is connected to a resistor having a resistance of 10 ohms . What is the current and power across the resistor ? Please answer my question.
current is 9/60 amps
power= I^2 r= (9/60)^2*10
To calculate the power absorbed by the 10-ohm resistor, you need to use the formula P = I^2 * R, where P is the power, I is the current, and R is the resistance.
To find the current, you can use Ohm's Law, which states that V = I * R, where V is the voltage and R is the resistance.
In this case, the voltage is 9 volts, and the total resistance is the sum of all the resistors in series: 10 ohms + 20 ohms + 30 ohms = 60 ohms.
Using Ohm's Law, you can calculate the current:
I = V / R = 9V / 60Ω = 0.15 A
Now that you have the current, you can calculate the power absorbed by the 10-ohm resistor:
P = I^2 * R = (0.15 A)^2 * 10Ω = 0.0225 * 10 W = 0.225 W
Therefore, the power absorbed by the 10-ohm resistor is 0.225 watts.