Posted by Sara on Sunday, February 13, 2011 at 7:22pm.
Find the equation of a logarithmic function whose graph has x-intercept 8, a vertical asymptote at x=0, and which passes through the point (1/2,4)
- Math-Logarithmic function - Reiny, Sunday, February 13, 2011 at 9:26pm
Since I see numbers 1/2 , 4, and 8 I will use
log2 as my logarithm
Since the y-axis is an asymptote, there cannot be a horizontal shift of the standard log function, but there could be a vertical shift as well as a compression.
let the function by
y = alog2x + k
point (8,0) is on it, so
0 = alog28 + k
0 = a(3) + k , (#1)
point (1/2,4 lies on it, so
4 = alog2(1/2) + k
4 = a(-1) + k , (#2)
subtract #1 from #2
4 = -4a
a = -1
then 0 = -3+k
k = 3
so one possible log function would be
y = - log2x + 3
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