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October 1, 2014

October 1, 2014

Posted by **alex** on Sunday, February 13, 2011 at 6:41pm.

i. g(x) = A-f(x) where A is a constant

ii. for the integral of 1 to 2 f(x)dx= the integral of 2 to 3 of g(x)dx

iii. for the integral from 2 to 3 f(x)dx = -3A

a find the integral from 1 to 3 of f(x)dx in terms of A.

b. find the average value of g(x) in terms of A, over the interval [1,3]

c. Find the value of k if the integral from 0 to 1 f(x+1)dx=kA

need the steps for these problems worked out plz

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