Analysis of a reaction mixture showed that
it had the composition 0.417 mol/L N2,
0.539 mol/L H2, and 0.127 mol/L NH3 at
800 K, at which temperature Kc = 0.278 for
N2(g) + 3H2(g) *) 2NH3(g) .
Calculate the reaction quotient Qc .
how's the quest going friendos
Qc = (NH3)^2/(H2)^3(N2)
Substitute the numbers and solve.
^shots fired
oh shi, dad you got roasted
Son. Just quit. Being a math doctor is not good for you ;)
To calculate the reaction quotient Qc, we use the formula:
Qc = [NH3]^2 / ([N2] * [H2]^3)
Where [NH3], [N2], and [H2] are the molar concentrations of NH3, N2, and H2, respectively.
Given the composition of the reaction mixture:
[N2] = 0.417 mol/L
[H2] = 0.539 mol/L
[NH3] = 0.127 mol/L
Plugging these values into the formula, we get:
Qc = (0.127 mol/L)^2 / ((0.417 mol/L) * (0.539 mol/L)^3)
Calculating the values:
Qc = 0.016129 mol^2/(L^2) / (0.417 mol/L * (0.539 mol/L)^3)
Now, let's simplify the equation:
Qc = 0.016129 mol^2/(L^2) / (0.417 mol/L * 0.539 mol^3/L^3)
At this point, let's calculate the values in the denominator:
Qc = 0.016129 mol^2/(L^2) / (0.417 mol/L * 0.12954 mol^3/L^3)
Now, divide the numerator by the denominator:
Qc = 0.016129 / (0.417 * 0.1295^3)
Finally, calculate the value of Qc:
Qc = 0.016129 / (0.417 * 0.00218)
Qc ≈ 17.48
Therefore, the value of the reaction quotient Qc is approximately 17.48.