Posted by Anonymous on Sunday, February 13, 2011 at 5:58pm.
To find the distance from the house at A to the house at B, a surveyor measures the angle ACB, which is found to be 70°, and then walks off the distance to each house, 50 feet and 70 feet, respectively. How far apart are the houses?
feet

college Trig  helper, Sunday, February 13, 2011 at 6:11pm
Triangle ACB, C = 70 deg, a = 70, b = 50
find side c
Use Law of CosinesCase III
(Given two sides and the included angle)
c^2 = a^2 + b^2  2ab cos C
c^2 = 70^2 + 50^2  2(70)(50) cos 70
Solve for c

college Trig  Anonymous, Wednesday, December 2, 2015 at 11:46am
2966.76
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