Posted by
**randy** on
.

1. logaB = 2 and logbC = 4, evaluate logcA

*the lowercase letters are bases ie. log(base a)B

2. solve for x: (log(base 2)x))^3 = log(base 2)x

Thursday

March 30, 2017
Posted by
**randy** on
.

1. logaB = 2 and logbC = 4, evaluate logcA

*the lowercase letters are bases ie. log(base a)B

2. solve for x: (log(base 2)x))^3 = log(base 2)x

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