Posted by Katrina on Sunday, February 13, 2011 at 2:10pm.
(heat to move ice from -13 to 0) + heat to melt ice) + (heat to move melted ice from 0 to final) + (heat lost by 112 g H2O @ 80) = 0
[(mass ice x specific heat ice x (0-(-13))] + [mass ice x heat fusio] + [mass melted ice x specific heat water x (Tfinal-Tinitial)] + (mass water x specific heat water x (Tfinal-Tinitial)] = 0
Solve for Tfinal. Answer is close to 63 C.
Related Questions
chemistry - A 13.0-g sample of ice at -13.0°C is mixed with 105.0 g of water...
Chemistry - When 112 g of water at a temperature of 22.5°C is mixed with 65....
Chemistry - A 19.6 g sample of ice at -10.0°C is mixed with 100.0 g of water...
Chemistry - A 14.0-g sample of ice at -18.0°C is mixed with 122.0 g of water...
Chemistry - A 30.0 gram sample of water at 280. K is mixed with 50.0 grams of ...
Chemistry - A 300.0g sample of ice at -30.OC is mixed with 300.0G of water at ...
Chemisrty - A 10.0 g sample of ice at -14.0°C is mixed with 124.0 g of water...
biology - A 28.0-g sample of ice at -18.0°C is mixed with 124.0 g of water ...
Chemistry - A 24.0 g sample of ice at -19.0°C is mixed with 118.0 g of water...
Chemistry - A .25 g chunk of sodium metal is cautiously dropped into a mixture ...
For Further Reading
