A 2.50- object is moving along the axis at 1.60 . As it passes the origin, two forces and are applied, both in the direction (plus or minus); .The forces are applied for 3.00 , after which the object is at the point , .
What is F2?
To find the value of F2, we need to use Newton's second law of motion. According to the second law, the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
Given:
Mass of the object (m) = 2.50 kg
Initial velocity (v) = 1.60 m/s
Time (t) = 3.00 s
First, we need to calculate the object's acceleration (a).
Using the formula:
Acceleration (a) = (Final velocity - Initial velocity) / Time
As the object is at rest after 3 seconds, the final velocity is 0 m/s.
a = (0 - 1.60) / 3.00
Next, we determine the net force (Fnet) acting on the object.
Using the formula:
Fnet = m * a
Fnet = 2.50 * ((0 - 1.60) / 3.00)
Now, we need to find F2, which is one of the forces applied on the object.
The net force is the vector sum of the individual forces, so:
Fnet = F1 + F2
Rearranging the equation, we can find F2:
F2 = Fnet - F1
To find F1, we would need additional information or a given value for it.
Please provide the value of F1 in order to calculate F2 accurately.