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April 1, 2015

April 1, 2015

Posted by **Kristen** on Sunday, February 13, 2011 at 7:24am.

- Precalculus -
**bobpursley**, Sunday, February 13, 2011 at 8:13amIsn't

x= rcosTheta=costheta (sqrt 6/sin2U))

I suspect you can get sin2U into a form that will reduce the equation.

y= rsinTheta

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