Precalculus
posted by Kristen on .
how do you put the polar equation r^2(sin2u)=6 into rectangular form?

Isn't
x= rcosTheta=costheta (sqrt 6/sin2U))
I suspect you can get sin2U into a form that will reduce the equation.
y= rsinTheta
posted by Kristen on .
how do you put the polar equation r^2(sin2u)=6 into rectangular form?
Isn't
x= rcosTheta=costheta (sqrt 6/sin2U))
I suspect you can get sin2U into a form that will reduce the equation.
y= rsinTheta