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October 23, 2014

October 23, 2014

Posted by **Janet** on Saturday, February 12, 2011 at 8:46pm.

g(x)= x, x<-3

5x/(x^2-4x), x>= -3

- calculus -
**MathMate**, Saturday, February 12, 2011 at 9:59pmEvaluate g(x) at points close to the discontinuity:

Lim x-> -3^{-}g(x) = -3

g(-3)=5(-3)/((-3)^2-4(-3))

=-15/21

=-5/7

So there is a jump from -3 on the left to -5/7 on the right.

Can you suggest what kind of discontinuity it is?

- calculus -
**Janet**, Saturday, February 12, 2011 at 10:19pmI assume it's a jump since it jumps from one value to another.

- calculus -
**MathMate**, Sunday, February 13, 2011 at 8:22amThat is correct.

If you do not have clear definitions of each type of discontinuity, you can check the following link:

http://en.wikipedia.org/wiki/Classification_of_discontinuities

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