Posted by **Kimi** on Saturday, February 12, 2011 at 3:53pm.

Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 120 miles per hour. Train A passes a station at 5:10pm. If train B passes the same station at 5:25pm, at what time will train B catch train A.

- Algebra -
**helper**, Saturday, February 12, 2011 at 4:30pm
D = RT (Distance = Rate * Time)

120 = rate of Train B

T = time of Train B

120T = distance of Train B

100 = rate of Train A

T + 0.25 = time of Train A (5:25 - 5:10 = 15 min = 60/15 = 0.25 h)

100(T + 0.25) = distance of Train A

Distances are equal

120T = 100(T + 0.25)

120T = 100T + 25

20T = 25

T = 1.25 h

Train B will catch up in 1.25 hours

I'll let you determine the time B catches train A.

- Algebra -
**Kimi**, Saturday, February 12, 2011 at 4:36pm
Thank you. for some reason these type problems blow my mind. I cannot figure out how to put them together to solve them. I am so thankful to everyone on this site that has helped me at one time or another. THANKS!!!

- Algebra -
**helper**, Saturday, February 12, 2011 at 4:57pm
You're welcome :)

- Algebra -
**Anonymous**, Friday, October 28, 2011 at 9:26pm
train a and b are traveling in the same direction on parellel tracks. train a is traveling at 100 miles per hour and train b at 110 miles per hour.train a passes the station at8:25 and train b passes the same station at 8:55 what time will train b catch up to train a

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