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Posted by on Saturday, February 12, 2011 at 2:45pm.

A 5.00 g bullet moving at 648 m/s strikes a 670 g wooden block at rest on a frictionless surface. The bullet emerges, traveling in the same direction with its speed reduced to 440 m/s.
A 5.00 g bullet moving at 648 m/s strikes a 670 g wooden block at rest on a frictionless surface. The bullet emerges, traveling in the same direction with its speed reduced to 440 m/s.
(a) What is the resulting speed of the block?

(b) What is the speed of the bullet-block center of mass?
(b) What is the speed of the bullet-block center of mass?

  • AP PHYSICS MECH. - , Saturday, February 12, 2011 at 3:17pm

    Momentum before = 648 * .005
    equals
    Momentum after = 440*.005 + v * .670
    solve for v
    v = 1.55 m/s

    Speed of center of mass does not change because total mass does not change

    b)before : average speed = (648*.005 + 0*.670)/.675 = 4.8 m/s

    c) after: average speed = (440*.005 + 1.55*.670)/.675 = 4.8 m/s sure enough

  • AP PHYSICS MECH. - , Sunday, February 13, 2011 at 2:35pm

    Thank you :)

  • AP PHYSICS MECH. - , Sunday, December 16, 2012 at 1:04pm

    I like birds

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