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January 28, 2015

January 28, 2015

Posted by **malcolm** on Saturday, February 12, 2011 at 12:53pm.

- calculus differential equation -
**bobpursley**, Saturday, February 12, 2011 at 3:56pmdy/dx=2(first )/y^2 (second)

y^2 dy=2(first)dx/(second)

so lets look at the right side.

2(e^x-e^-x)/(e^x+e^-x)^4

factor out e^-x

numerator: 2e^-x(e^2x)

denominator(factor out e^-4x)

e^-4x (e^2x-1)^2

so you are left on the right side:

2*e^3x(e^2x -1)/(e^2x+1) dx

or = 2(e^5x)/(e^2x+1) dx + 2e^3x/(e^2x+2) dx

- calculus differential equation -
**mike**, Tuesday, February 15, 2011 at 12:41pmthanks Bob much appreciated. Do I then take the integral of the last line? And is the left hand side 1/3y^3 (from y^)? I do not know how this fits together. Thanks for any further help

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