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April 16, 2014

Homework Help: Calculus - not sure if my work is correct?

Posted by Amy on Saturday, February 12, 2011 at 9:24am.

A 15ft ladder leans against a building and its base starts to slide down the wall. The base is moving at a rate of 5ft/sec when the base is 9ft from the wall. How fast is the top of the ladder moving at this moment? What is the rate of change of the angle formed by the ladder and the ground?

I know that this forms a right triangle with a hypotenuse of 15 an two legs that measure 9 (for x) and 12 (for y).

My first step was:
x dx/dt + y dy/dt = z dz/dt
9(5) + 12 dy/dt = 15(0)
dy/dt = 3.75 ft/sec

Then I attempted to answer the second part of the question, but I wasn't sure how to do this.
What I did was:
A=1/2bh or 1/2xy
dA/dt = 1/2 x dy/dt + 1/2 y dx/dt
dA/dt = 1/2(9)(3.75) + 1/2(-12)(5)
dA/dt = -105/8 ft^2/sec

-------> I'm not sure if this is the right process or if I'm supposed to be looking for an angle? Any help is appreciated, thanks

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