3 objects of mass 1,0kg,1,5kgand 0,5kg respectively,are suspended by means of a thin string .how great is the tension that the string experiences?
total of 3 kg ?
T = (3 * 9.8) newtons
24.9
To determine the tension in the string, we need to consider the forces acting on each object and apply Newton's second law of motion.
Let's label the three objects as Object A, Object B, and Object C, with masses of 1.0kg, 1.5kg, and 0.5kg respectively.
First, let's determine the force of gravity acting on each object by multiplying their mass by the acceleration due to gravity, which is approximately 9.8 m/s^2 on Earth.
Force of gravity on Object A = mass of A * acceleration due to gravity = 1.0kg * 9.8 m/s^2 = 9.8N
Force of gravity on Object B = mass of B * acceleration due to gravity = 1.5kg * 9.8 m/s^2 = 14.7N
Force of gravity on Object C = mass of C * acceleration due to gravity = 0.5kg * 9.8 m/s^2 = 4.9N
Since the objects are suspended by a thin string, the tension in the string will be equal to the sum of the forces acting on each object.
Tension in the string = Force of gravity on A + Force of gravity on B + Force of gravity on C
= 9.8N + 14.7N + 4.9N
= 29.4N
Therefore, the tension experienced by the string is 29.4 Newtons.