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Posted by **uriel** on Friday, February 11, 2011 at 11:59pm.

The equation for the height of the ball is y = −16t2 + vt + s

where v is the initial velocity, t is in seconds, and s is the initial height.

How high can she throw a ball? Answer in units of ft.

- algebra -
**Reiny**, Saturday, February 12, 2011 at 8:39amIn the form of the equation you are using, v is the initial velocity, so

y = -16t^2 + 11t + s

The maximum height would be obtained at the vertex of this parabola.

the x of the vertex is -11/-32 seconds or .34 seconds

then y = -16(.34)^2 + 11(.34) + s = 1.89 + s

unless she is about 8 feet tall, she is not going to make it.

(s will be the initial height, probably the position of her hand)

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