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December 20, 2014

December 20, 2014

Posted by **art** on Friday, February 11, 2011 at 11:02pm.

how do you figure this out?

- calculus -
**Reiny**, Friday, February 11, 2011 at 11:07pmsince your function is a straight line

and it is in the form f(x) = mx + b

the slope anywhere on the line is -5

no work needed here.

- calculus -
**Allison**, Friday, February 11, 2011 at 11:09pmTo find the slope of the tangent line you have to take the first derivative of f(x). So f'(x)=-5. Or you can also see that from the formula y=mx+b, where m is slope and b is your y intercept, that -5 is the slope. Because the original function is a line, the slope is the same at every point.

- calculus -
**helper**, Friday, February 11, 2011 at 11:10pmTo find the slope of the tangent line at a point means to find the derivative of f(x).

f(x) = 3 - 5x

f' = 0 - 5

f' = -5

Then, normally, you would plug in the given point, (-1, 8), to find the slope.

But since f' = 5 with no variable x, for instance, there is nowhere to plug in the point.

Therefore, the slope is everywhere.

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