Calculate the specific volume of an air-vapour mixture when the temp=30 degree Celsius, Mw=0.015 kg/kg, Pt=90kpa

To calculate the specific volume of an air-vapour mixture, you can use the ideal gas law. The ideal gas law relates the pressure, volume, temperature, and the amount of gas present.

The equation for the ideal gas law is:

PV = nRT

Where:
P is the pressure of the gas
V is the volume it occupies
n is the number of moles of gas
R is the ideal gas constant
T is the temperature in Kelvin

To calculate the specific volume, we need to rearrange the ideal gas law equation to solve for volume (V):

V = nRT / P

In this case, we are given the following information:
- Temperature (T) = 30 degrees Celsius
- Molecular weight (Mw) = 0.015 kg/kg
- Pressure (Pt) = 90 kPa

However, before we can proceed with the calculation, we need to convert the given temperature to Kelvin since the ideal gas law requires temperature in Kelvin.

To convert from Celsius to Kelvin, use the equation:

T(K) = T(°C) + 273.15

T(K) = 30 + 273.15
T(K) = 303.15 K

Now we have all the necessary information to calculate the specific volume.

Assuming we know the number of moles of the air-vapour mixture, we can substitute the values into the equation:

V = nRT / P

Specific volume = V / Mw

Remember, we also need to convert the pressure from kPa to Pascal (Pa), as the ideal gas law requires pressure in Pascal.

1 kPa = 1000 Pa

Therefore, the pressure (P) in Pascal would be:

P = 90 kPa * 1000 Pa/kPa
P = 90000 Pa

After calculating the values, substitute them into the equation:

Specific volume = nRT / P

However, we need the number of moles (n) to proceed with the calculation. If you have the moles of air-vapour mixture, you can use the ideal gas law to solve for the specific volume.