Two charges, Q1= 3.20 microCoulombs, and Q2=5.90 microCoulombs, are located at points (0,-2.00cm) and (0,+2.00cm.

What is the magnitude of the electric field at point P, located at (5.00cm,0), due to Q1 alone?

what is the distance from 0.-.02 to .05,0?

distance= sqrt((.05^2)+(.02)^2) check that.

then E=kq/distance^2

To find the magnitude of the electric field at point P due to Q1, we can use Coulomb's law. Coulomb's law states that the electric field due to a point charge is given by:

E = k * (Q / r^2)

where E is the electric field, k is the Coulomb's constant (k = 8.99 x 10^9 N m^2/C^2), Q is the charge, and r is the distance between the point charge and the location where you want to find the electric field.

In this case, we want to find the electric field at point P due to Q1. The charge of Q1 is given as Q1 = 3.20 microCoulombs (or 3.20 x 10^-6 C). The distance between Q1 and point P is 5.00 cm (or 5.00 x 10^-2 m).

Plugging these values into Coulomb's law, we get:

E = (8.99 x 10^9 N m^2/C^2) * (3.20 x 10^-6 C) / (5.00 x 10^-2 m)^2

Calculating this expression will give us the magnitude of the electric field at point P due to Q1.