Given ABCD is a square

AC = BD = 4 units

Find coordinates of ABCD

To find the coordinates of the square ABCD, we need to know the coordinates of just one vertex of the square. Let's assume that vertex A is located at the origin (0, 0).

Since AC = BD = 4 units and ABCD is a square, we know that the length of each side of the square is also 4 units.

Starting from point A at (0, 0), we can find the coordinates of the other vertices of the square as follows:

1. B: Since AD is parallel to the y-axis and AD = 4 units, B will have the same x-coordinate as A but with an increase in the y-coordinate by 4 units. Therefore, B is located at (0, 4).

2. C: Since BC is parallel to the x-axis and BC = 4 units, C will have the same y-coordinate as B but with an increase in the x-coordinate by 4 units. Therefore, C is located at (4, 4).

3. D: Since CD is parallel to the y-axis and CD = 4 units, D will have the same x-coordinate as C but with a decrease in the y-coordinate by 4 units. Therefore, D is located at (4, 0).

To summarize, the coordinates of the vertices of the square ABCD are:

A(0, 0)
B(0, 4)
C(4, 4)
D(4, 0)