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Calculate the pH after 0.12 mol of NaOH is added to 1.00 L of 0.60 M HF and 1.06 M KF

  • chem - ,

    ...........HF + NaOH ==> NaF + H2O
    begin....0.6 mol..0.12...1.06
    change..-0.12......-0.12.+0.12
    equil...0.48........0.....1.18
    Use the Henderson-Hasselbalch equation
    pH = pKa + log [(base)/(acid)]
    NaF is the base. HF is the acid. pKa is that of HF.

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