Posted by michele on Friday, February 11, 2011 at 2:36pm.
...........HF + NaOH ==> NaF + H2O
begin....0.6 mol..0.12...1.06
change..-0.12......-0.12.+0.12
equil...0.48........0.....1.18
Use the Henderson-Hasselbalch equation
pH = pKa + log [(base)/(acid)]
NaF is the base. HF is the acid. pKa is that of HF.
Related Questions
chem - Calculate the pH after 0.12 mol of NaOH is added to 1.00 L of 0.60 M HF ...
chemistry - Calculate the pH after 0.15 mol of NaOH is added to 1.00 L of the ...
Chemistry - Calculate the pH after 0.13 mol of NaOH is added to 1.00 L of the ...
Chemistry - Calculate the pH after 0.10 mol of HCl is added to 1.00 L of the ...
Chem - A) Calculate the pH of a buffer system that is 0.06 M HNO2 and 0.160 M ...
CHEMISTRY - A BUFFER SOLUTION IS MADE FORM 0.10 MOLES NaF AND 0.25 MOLES OF HF ...
chem - a buffer is made by adding 150 ml of .595M BaF2 and 0f .500M of HF ...
CHEM - Which of the following mixtures will result in the formation of a buffer ...
chemistry - A 50.00ml sample of 0.200M hydroflouric acid (HF) is titrated with ...
chemistry - A chemist wishes to prepare 250mL of a buffer that is pH = 4.50. ...
For Further Reading
