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Posted by **Shannon** on Friday, February 11, 2011 at 11:51am.

a) find the diving speed of the hawk

b)what angle did the hawk make with the horizontal during its descent?

c)for how long did the mouse enjoy free fall?

- Physics HELP ASAP PLEASE -
**JIntorcio**, Wednesday, September 28, 2011 at 6:12pmOK, so first I'd do the equation in the Y direction to find the answer to part 3).

X = Xo + Vot + 1/2at^2

3 = 180 + (0*t) + (1/2 * -9.8 * t^2)

3 = 180 - 4.9t^2

4.9 t^2 = 177

t^2 = 36.12

t = 6.01s

Now we go back to part 1). We know the Hawk waited 2s before starting its dive so it dove for 6.01 - 2 = 4.01 s. We also know that during that time, it traveled 180 - 3 = 177 m vertically. But, since there's no air resistance, the mouse kept traveling horizontally too! And, during those 6.01s, it traveled 10 * 6.01 = 60.1 m forward. Since the Hawk traveled 20 m in the 2 s it waited, it must have traveled 60.1 - 20 = 40.1 m horizontally during it's dive!

OK, so it dove 177 m vertically while traveling 40.1 m horizontally. Pythagorean theorem then says d = sqrt(177^2 + 40.1^2) = 181.5 m. Since it did that in 4.01 s, its speed must have been 181.5 / 4.01 = 45.26 m/s.

We can calculate the angle... Draw a picture and you may see...

tan(theta) = 177 / 40.1 = 4.414

theta = 1.348 rad or 77.2°

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