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October 30, 2014

October 30, 2014

Posted by **verenice** on Friday, February 11, 2011 at 10:07am.

- geometry -
**Reiny**, Friday, February 11, 2011 at 10:24amLet ABC be the right-angled triangle with angleB = 90°

let the bisector angle B be BD where D is on the hypotenuse AC

We know that AD : DC = areaABD : areaBCD

areaABD = (1/2)(12)(BD)sin45°

areaBCD = (1/2)(5)(BD)sin45°

then areaABD : areaBCD = 12 : 5

so AD = (12/17)(13) = 9.2

and DC = 13-9.2 = 3.8

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