determine the molarity of a 18 ml sample of HCl solution that is required to prepare 30 ml of 2.3 M HCl solution?
To determine the molarity of a solution, you need to use the equation:
Molarity (M) = (moles of solute) / (volume of solution in liters)
In this case, you have an 18 ml sample of HCl solution and you want to know the molarity of this solution.
First, let's determine the moles of solute in the 18 ml sample. We can do this by using the equation:
moles of solute = (molarity) x (volume of solution in liters)
Since we have the volume of the solution in milliliters, we need to convert it to liters. There are 1000 ml in 1 liter, so:
Volume of solution in liters = 18 ml / 1000 ml/L = 0.018 L
Now we can calculate the moles of solute:
moles of solute = (molarity) x (volume of solution in liters) = M x 0.018 L
To find the molarity, we need more information. You mentioned that the 18 ml sample is used to prepare a 30 ml solution of 2.3 M HCl.
Based on this information, we can use the equation for dilution:
M1 x V1 = M2 x V2
Where:
M1 = initial molarity of the solution
V1 = initial volume of the solution
M2 = final molarity of the solution
V2 = final volume of the solution
Given:
M1 = ? (unknown)
V1 = 18 ml
M2 = 2.3 M
V2 = 30 ml
We can plug in the values into the equation and solve for M1:
M1 x V1 = M2 x V2
M1 x 18 ml = 2.3 M x 30 ml
M1 = (2.3 M x 30 ml) / 18 ml
Now that we have M1, we can substitute this value back into the moles of solute equation to find the molarity of the 18 ml sample:
Molarity = moles of solute / (volume of solution in liters)
Molarity = (M1 x 0.018 L) / 0.018 L
Therefore, to determine the molarity of the 18 ml sample of HCl solution, you need to substitute the calculated value of M1 back into the equation and simplify the expression.