Posted by **Anonymous** on Friday, February 11, 2011 at 12:00am.

An airplane has a velocity relative to the air of 181 m/s in a westerly direction. If the wind has a speed relative to the ground of 53 m/s directed to the north, what is the speed of the plane relative to the ground?

- physics -
**Henry**, Sunday, February 13, 2011 at 6:17pm
Vpg = Vpa + Vag

Vpa = -181m/s @ 180deg.

Vag = 53m/s @ 90deg.

V(hor) = -181cos180 + 53cos90,

V(hor) = 181 + 0 = 181m/s.

V(ver) = -181sin180 + 53sin90,

V(ver) = 0 + 53 = 53m/s.

V^2 = X^2 + Y^2,

V^2 = (181)^2 + (53)^2,

V^2 = 32761 + 2809 = 35570,

V=sqrt(35570) = 189m/s=Speed of plane relative to ground.

- physics -
**Henry**, Sunday, February 13, 2011 at 6:28pm
DEFINITIONS

Vpg = Speed of plane relative to ground.

Vpa = Speed of plane relative to air.

Vag = Speed of air relative to ground.

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