What is the percent by mass of 3.55 g NaCl dissolved in 88 g H2O?

2. A solution is made by adding 1.23 moles of KCl to 1000.0 g of water. What is the % by mass of KCl in this solution?

3. If you have 100.0 mL of a 25% aqueous solution of ethanol, what volumes of ethanol and water are in the solution?

4. What is the percent by volume of isopropyl alcohol in a solution that contains 24 mL of isopropyl alcohol in 1.1 L of water?

5. What is the Molarity of an aqueous solution containing 160.0 g of ammonium nitrate (NH4NO3) in 2500 m L of solution?

6. What is the Molarity of a bleach solution containing 11.7 g of NaOCl per liter of bleach?

7. Calculate the Molarity of 2.30 L of a solution containing 2.45 g of dissolved KBr.

8. How many moles of solute are contained in 15.25 mL of 2.10 M CaCl2?

9. How many grams of KOH are in 64.3 mL of a 0.0238M KOH solution?

10. What volume of a 3.00M KI stock solution would you use to make 0.300 L of a 1.25M KI solution?

can you please help me

See your post above.

Of course! I'd be happy to help you with these questions. Let's go through each of them step by step.

1. The percent by mass can be calculated by dividing the mass of the solute (NaCl) by the total mass of the solution (NaCl + H2O) and multiplying by 100. So, to find the percent by mass of NaCl:

Percent by mass = (mass of NaCl / mass of solution) x 100

Therefore, the percent by mass of 3.55 g NaCl dissolved in 88 g H2O is:

Percent by mass = (3.55 g / (3.55 g + 88 g)) x 100

2. The percent by mass of KCl in the solution can be calculated in a similar manner. First, find the mass of KCl by multiplying the number of moles (1.23 moles) by the molar mass of KCl, then divide the mass of KCl by the mass of the solution (KCl + water) and multiply by 100.

Mass of KCl = moles of KCl x molar mass of KCl

Percent by mass = (mass of KCl / mass of solution) x 100

3. To find the volumes of ethanol and water in the solution, you need to know the concentration of ethanol in the solution. Since the solution is labeled as a 25% aqueous solution of ethanol, it means that 25 mL of ethanol is present per 100 mL of solution. Therefore, 25 mL of ethanol is present in every 125 mL of the solution. The rest of the volume (125 mL - 25 mL = 100 mL) would be water.

4. The percent by volume of isopropyl alcohol can be calculated by dividing the volume of isopropyl alcohol by the total volume of the solution (isopropyl alcohol + water) and multiplying by 100.

Percent by volume = (volume of isopropyl alcohol / volume of solution) x 100

5. Molarity (M) is calculated by dividing the number of moles of solute (ammonium nitrate) by the volume of the solution in liters.

Molarity (M) = (moles of solute / volume of solution in liters)

6. The Molarity of a solution can be calculated by dividing the number of moles of solute (NaOCl) by the volume of the solution in liters.

Molarity (M) = (moles of solute / volume of solution in liters)

7. To calculate the Molarity of a solution, you need to know the number of moles of solute (KBr) and the volume of the solution (in liters). Once you have these values, you divide the number of moles of solute by the volume of the solution.

Molarity (M) = (moles of solute / volume of solution in liters)

8. The number of moles of solute (CaCl2) can be calculated by multiplying the volume of the solution (in liters) by the molarity (M) of the solution.

Moles of solute = volume of solution (in liters) x molarity (M)

9. To calculate the mass of KOH in the solution, you can use the formula:

Mass of KOH = volume of solution (in liters) x molarity (M) x molar mass of KOH

10. To determine the volume of the 3.00M KI stock solution needed to make 0.300 L of a 1.25M KI solution, you can use the formula:

Volume of stock solution (in liters) x molarity of stock solution = volume of desired solution (in liters) x molarity of desired solution

Let me know if you have any specific question you would like me to focus on or if you need more clarification on any of the steps involved.