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April 18, 2015

April 18, 2015

Posted by **claire** on Thursday, February 10, 2011 at 9:30pm.

- trig -
**MathMate**, Thursday, February 10, 2011 at 11:42pm2sinx-1=cscx

2sin(x)-1 = 1/sin(x)

2sin²(x)-sin(x)-1=0

(2sin(x)+1)(sin(x)-1)=0

sin(x)=-1/2 or sin(x)=1

can you take it from here?

Note that sin(x) is positive in the first and second quadrants.

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