find the lengths of the sides of a triangle whose perimeter is 37. The measure of the first side of the triangle is 8 less than the second side, and the second side is twice the length of the third side

third side --- x

second --- 2x
first---- 2x - 8

can you solve
x + 2x + 2x-8 = 37 ?

x=9

If the perimeter of the first triangle is 21 m, what is the perimeter of the second?

To find the lengths of the sides of the triangle, we can use algebraic equations based on the given information.

Let's assume the lengths of the sides of the triangle are:
- First side: x
- Second side: y
- Third side: z

According to the given information:

1) The measure of the first side of the triangle is 8 less than the second side:
x = y - 8

2) The second side is twice the length of the third side:
y = 2z

Now, we can use these equations to express the perimeter of the triangle and solve for the variables.

Perimeter of a triangle = Sum of all side lengths

Substituting the values from the given information, we have:
37 = x + y + z

Plugging in the expressions from equations (1) and (2), we get:
37 = (y - 8) + y + z

Simplifying the equation further, we have:
37 = 2y - 8 + z

Rearranging the terms, we get:
2y + z = 45

We now have an equation with two variables. To proceed, we need another equation to solve for both variables. However, we can see that the third side (z) doesn't have any constraints or relations provided. Therefore, it's not possible to determine the exact lengths of all sides of the triangle with the information given.