The length of a rectangular piece of property if 1 foot more than twice the width. If the perimeter is 302 feet, find the length and width.
w = width
2w + 1 = length
P = 2w + 2L
302 = 2w + 2(2w + 1)
Solve for w, the width.
length = 2w + 1
43
To find the length and width of the rectangular piece of property, we can set up a system of equations using the given information.
Let's assume:
Width of the rectangular piece of property = x feet
According to the given information, the length is 1 foot more than twice the width:
Length of the rectangular piece of property = 2x + 1 feet
The perimeter of a rectangle is given by the formula:
Perimeter = 2(Length + Width)
Given that the perimeter is 302 feet, we can set up the equation as follows:
302 = 2(2x + 1 + x)
Simplifying the equation:
302 = 2(3x + 1)
302 = 6x + 2
300 = 6x
x = 50
Now that we know the width is 50 feet, we can find the length by substituting this value back into the equation for the length:
Length = 2x + 1
Length = 2(50) + 1
Length = 101
Therefore, the length of the rectangular piece of property is 101 feet and the width is 50 feet.