A 1L flask is filled with 1.000atm of H2 and 2.000atm of I2 at 448*C. The following

equilibrium is established: H2(g)+I2(g)=
2HI(g). The value of K for this equilibri-
um is 50.5. What are equilibrium partial
pressures of H2,I2,and HI?

Kc = Kp = 50.5

I would convert to moles since you know P, V, R, and T.

............H2 + I2 ==> 2HI
begin.....0.0169 0.0338..0
change.....-x......-x.....2x
equil....0.0169-x 0.0338-x..2x

Substitute into K and solve for x and determine equilibrium concns of H2, I2, and HI. Then use PV = nRT to convert ot partial pressures.
There may be an easier way to do this but this will work.

To find the equilibrium partial pressures of H2, I2, and HI, we can use the concept of stoichiometry and the given equilibrium constant, K.

Step 1: Write the balanced equation for the reaction:
H2(g) + I2(g) ⇌ 2HI(g)

Step 2: Define the initial and equilibrium conditions:
- Initial pressure of H2: 1.000 atm
- Initial pressure of I2: 2.000 atm
- Initial pressure of HI: 0 atm (as it is not present initially)
- Equilibrium pressure of H2: PH2 (unknown)
- Equilibrium pressure of I2: PI2 (unknown)
- Equilibrium pressure of HI: PHI (unknown)

Step 3: Write the expression for the equilibrium constant (K):
K = (PHI^2) / (PH2 * PI2)

Step 4: Use the given value of K to solve for the equilibrium pressures of H2, I2, and HI:
K = 50.5
PH2 = 1.000 atm (given)
PI2 = 2.000 atm (given)

Rearranging the equilibrium constant expression:
PHI^2 = K * (PH2 * PI2)
PHI^2 = 50.5 * (1.000 atm * 2.000 atm)
PHI^2 = 101 atm^2

Taking the square root of both sides:
PHI = √(101 atm^2)
PHI = 10.05 atm

Therefore, the equilibrium partial pressure of HI is 10.05 atm.

Step 5: Determine the equilibrium partial pressures of H2 and I2 using the stoichiometry of the reaction:
Since the stoichiometric coefficient of H2 is 1, the pressure of H2 at equilibrium is the same as the initial pressure:
PH2 = 1.000 atm

Since the stoichiometric coefficient of I2 is also 1, the pressure of I2 at equilibrium is the same as the initial pressure:
PI2 = 2.000 atm

Therefore, the equilibrium partial pressures of H2 and I2 are 1.000 atm and 2.000 atm, respectively.

In summary, the equilibrium partial pressures of H2, I2, and HI are 1.000 atm, 2.000 atm, and 10.05 atm, respectively.