Posted by crystal on Thursday, February 10, 2011 at 12:25am.
V = s^3
dV/dt = 3s^2 ds/dt
= 3s^2(.05)
= .15 s^2
I don't think your question was complete.
It probably said "what is the rate of change of the volume of the cube, in cm^3/sec, when s = ...."
Sub in the value of the given s into the dV/dt,
otherwise the above answer stands as is.
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