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April 1, 2015

Posted by **crystal** on Thursday, February 10, 2011 at 12:25am.

- calculus -
**Reiny**, Thursday, February 10, 2011 at 12:49amV = s^3

dV/dt = 3s^2 ds/dt

= 3s^2(.05)

= .15 s^2

I don't think your question was complete.

It probably said "what is the rate of change of the volume of the cube, in cm^3/sec, when s = ...."

Sub in the value of the given s into the dV/dt,

otherwise the above answer stands as is.

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