Posted by T on Wednesday, February 9, 2011 at 10:33pm.
I would do this.
M + xHCl ==> MClx + Hx
If we started with 0.250 g M and ended with 0.427 g of the chloride, the amount of Cl added must be 0.427-0.250 = 0.177 grams. Convert that to moles by 0.177/35.453 = 0.00499 moles Cl atoms.
We know the formula is MCl2, MCl3 or MCl4; therefore, the 0.0499 moles Cl will have 1/4 moles of M if MCl4, 1/3 moles of M if MCl3, and 1/2 moles M if MCl2.
For 4, 0.00499/4 = 0.00112
For 3, 0.00499/3 = 0.00166
For 2, 0.00499/2 = 0.00250
moles M = grams/atomic mass and rearrange to atomic mass = grams/moles M and plug in the numbers.
For 4 (MCl4), 0.250/0.00112 = ??
For 3 (MCl3), 0.250/0.00166 = ??
For 2 (MCl2), 0.250/0.00250 = ??
Look on the periodic table and find the lanthanide element closest to one of your values.
There may be an easier way to solve this but this is the best I can think of at the moment.
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