Posted by **Amanda E.** on Wednesday, February 9, 2011 at 10:18pm.

Please help out. Thank you.

A right triangle has one leg on the x-axis. The vertex at the right end of that leg is at the point (3,0). The other vertex touches the graph os y=e^x. the entire triangle is to lie in the first quadrant. Find the maximum area of this triangle.Justify your answer.

My work:

A= (3-x)y/2

y=e^x

A=(3-x)(e^x)/2 <-- is this the right equation?

Thanks.

No one has answered this question yet.

- Repost- Calculus; someone please help -
**Kate**, Wednesday, February 9, 2011 at 10:21pm
Yes it is the right equation. Good job!

- Repost- Calculus; someone please help -
**Amanda E.**, Thursday, February 10, 2011 at 12:28am
is the max. area 3.6945?

thanks.

- Repost- Calculus; someone please help -
**MathMate**, Thursday, February 10, 2011 at 8:05am
Yes, that's correct too.

In exams and in general, if the number is a "round" number like e⊃2/2, I would give the answer as e²/2=3.6945(approx.)

because the latter is an approximation. This will give the exact value as the answer.

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