Posted by Amanda E. on Wednesday, February 9, 2011 at 10:18pm.
Please help out. Thank you.
A right triangle has one leg on the xaxis. The vertex at the right end of that leg is at the point (3,0). The other vertex touches the graph os y=e^x. the entire triangle is to lie in the first quadrant. Find the maximum area of this triangle.Justify your answer.
My work:
A= (3x)y/2
y=e^x
A=(3x)(e^x)/2 < is this the right equation?
Thanks.
No one has answered this question yet.

Repost Calculus; someone please help  Kate, Wednesday, February 9, 2011 at 10:21pm
Yes it is the right equation. Good job!

Repost Calculus; someone please help  Amanda E., Thursday, February 10, 2011 at 12:28am
is the max. area 3.6945?
thanks.

Repost Calculus; someone please help  MathMate, Thursday, February 10, 2011 at 8:05am
Yes, that's correct too.
In exams and in general, if the number is a "round" number like e⊃2/2, I would give the answer as e²/2=3.6945(approx.)
because the latter is an approximation. This will give the exact value as the answer.
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