Posted by **nina** on Wednesday, February 9, 2011 at 8:23pm.

How do you multipl (3a-2b)(4a+3b)??

- algebra -
**helper**, Wednesday, February 9, 2011 at 8:41pm
(3a-2b)(4a+3b)

Using FOIL-first, outer, inner, last

(3a - 2b)(4a + 3b)

First = 3a * 4a = 12a^2

Outer = 3a * 3b = 9ab

Inner = -2b * 4a = -8ab

Last = -2b * 3b = -6b^2

12a^2 + 9ab - 8ab - 6b^2

Combine like terms

12a^2 + ab - 6b^2

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