algebra
posted by nina on .
How do you multipl (3a2b)(4a+3b)??

(3a2b)(4a+3b)
Using FOILfirst, outer, inner, last
(3a  2b)(4a + 3b)
First = 3a * 4a = 12a^2
Outer = 3a * 3b = 9ab
Inner = 2b * 4a = 8ab
Last = 2b * 3b = 6b^2
12a^2 + 9ab  8ab  6b^2
Combine like terms
12a^2 + ab  6b^2