Posted by nina on Wednesday, February 9, 2011 at 8:23pm.
How do you multipl (3a2b)(4a+3b)??

algebra  helper, Wednesday, February 9, 2011 at 8:41pm
(3a2b)(4a+3b)
Using FOILfirst, outer, inner, last
(3a  2b)(4a + 3b)
First = 3a * 4a = 12a^2
Outer = 3a * 3b = 9ab
Inner = 2b * 4a = 8ab
Last = 2b * 3b = 6b^2
12a^2 + 9ab  8ab  6b^2
Combine like terms
12a^2 + ab  6b^2
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