The area of a rectangular athletic field is represented by the expression 16y^7+32y^5+80y^3 square meters. Write an algebraic expression to represent one possible set of dimensions (in the sense “length times width”) of the athletic field. Include correct units with your solution.

A = Lw

16y^7 + 32y^5 + 80y^3
Factor into 2 factors.
1st factor = w
2nd factor = L

To find the dimensions of the rectangular athletic field, we need to factor the given expression, which represents its area. Factoring will help us determine the length and width of the field.

The given expression is: 16y^7 + 32y^5 + 80y^3 square meters

Now, let's factor out the common term, 16y^3:
16y^3(y^4 + 2y^2 + 5)

Therefore, one possible set of dimensions of the athletic field can be expressed as:
Length = 16y^3 meters
Width = (y^4 + 2y^2 + 5) meters

So, the algebraic expression representing one possible set of dimensions of the athletic field is: 16y^3 * (y^4 + 2y^2 + 5) square meters.