Posted by **Amanda E.** on Wednesday, February 9, 2011 at 6:06pm.

A right triangle has one leg on the x-axis. The vertex at the right end of that leg is at the point (3,0). The other vertex touches the graph os y=e^x. the entire triangle is to lie in the first quadrant. Find the maximum area of this triangle.Justify your answer.

My work:

A= (3-x)y/2

y=e^x

A=(3-x)(e^x)/2 <-- is this the right equation?

Thanks.

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