FIND A POINT-SLOPE FROM THE EQUATION OF THE LINE SATISFYING THE CONDITIONS.
SLOPE -2, PASSING THROUGH (2,8)
y-8= -2(x-2)
First, please do not use all capitals. Online it is like SHOUTING. Not only is it rude, but it is harder to understand. Thank you.
To find the equation of a line in point-slope form that satisfies the given conditions (slope = -2, passing through the point (2,8)), you can follow these steps:
Step 1: Start with the point-slope form of a linear equation, which is:
y - y₁ = m(x - x₁)
where (x₁, y₁) represents the given point and "m" represents the slope.
Step 2: Substitute the values of the slope and the coordinates of the given point into the equation. In this case:
m = -2, x₁ = 2, y₁ = 8
So the equation becomes:
y - 8 = -2(x - 2)
Step 3: Simplify the equation by distributing the -2 to the terms inside the parentheses:
y - 8 = -2x + 4
Step 4: Move the constant term (-8) to the other side of the equation by adding 8 to both sides:
y = -2x + 4 + 8
y = -2x + 12
So, the equation of the line with a slope of -2 and passing through the point (2,8) is y = -2x + 12 in point-slope form.