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April 20, 2014

April 20, 2014

Posted by **Mykmoloko** on Wednesday, February 9, 2011 at 10:01am.

- science -
**cheerie**, Thursday, May 5, 2011 at 6:20amuse formula vfy= viy+gt...

vfy= 0, this is always true when the object reaches its maximum height.

viy= vi sin degress (horizontal)

viy= 120sin 60

viy= 103.92

g= -9.81 m/s2

thus:

vfy= viy + gt

0= 103.92 + (-9.81)(t)

t = -1o3.92/-9.81

1o.59seconds from the top of the cliff.

getting the time...

compute for the dy or the height from the top of the cliff...

dy= viyt + 1/2gt (time is squared)

add then the dy from the top of the cliff with the height of your cliff which is 5o to get the max.height.

using the new dy, (50 + the dy you computed from the top of the cliff), use the same formula of dy... now the viy is 0 since when the object is already falling, the final speed when the object has reached it max height is o, going down, the value vf will become the vi of the initial speed.

(im not sure but i guess this is how it is done)

the get the distance of the flight by:

dy=viyt - 1/2 gt2 (please square the t,cant do superscript here). Suppose you get the distance

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