Posted by **Mike** on Wednesday, February 9, 2011 at 9:15am.

Ok so i don't know how i got that answer i think i typed in a wrong formula or read something wrong. I got .8926 for the first one. And the second one i don't know what i am suppost to use from the first answer to get that. Can someone help me.

It is known that about 20% of car insurance policies include emergency road service. Suppose we randomly select 10 car insurance policies.

What is the probability that at least one policy will have emergency road service?

Answer

0.6242

0.3758

0.8926

0.2684

0.1074

What is the expected number of policies having emergency road service?

Answer

3.5

8.0

1.6

2.0

5.0

## Answer This Question

## Related Questions

- Probability and Statistics - Random Variables X and Y follow a joint ...
- Chemistry - Consider 57.5 mL of a solution of weak acid HA (Ka = 1.00 10-6), ...
- Algebra - Here is the problem: Given f(x)=-x^3+3x^2-2x+6, find f(-1), f(0), and ...
- Math, check my answer. thanks - Consider the following studentsâ€™ methods of ...
- Math Question - ( (0.1095 mmol/mL)(25 mL) - (0.1482 mmol/mL)(29.04 mL) ) / ( (...
- statistics - Help!!I have tried this several times and come up with wrong answer...
- Probability and Statistics - Random Variables X and Y follow a joint ...
- math,help - on one of last week homeworks i got this one wrong can someone ...
- Alegra - Suppose that a spreadsheet contains the following values. A1 6 B1 -4 C1...
- Probability and Satistics - Random Variables X and Y follow a joint distribution...

More Related Questions