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January 31, 2015

January 31, 2015

Posted by **Leanna** on Wednesday, February 9, 2011 at 6:39am.

A cubic polynomial function f is defined by:

f(x) = 4x^3 + ax^2 + bx + k

where a, b, and k are constants.

The function f has a local minimum at x= -1, and the graph of f has a point of inflection at x= -2.

a) Find the values of a and b

b) If ∫ (from 0 to 1) f(x) dx = 32, what is the value of k?

I found a=24 and b=36

i don't know about B)

- Calculus -
**MathMate**, Wednesday, February 9, 2011 at 6:56amFrom a=24,b=36,

we find

f'(x)=0 has roots at x=-3 and -1, so that checks.

f"(x)=0 has a root at x=-2, so that checks too.

To solve B, we integrate

f(x):=4*x^3+24*x^2+36*x+k

from 0 to 1:

I=∫f(x)dx

=x^4+8*x^3+18*x^2+k*x

Evaluate I from 0 to 1 to give k+27

But since is given as I=32, so

I=32=k+27

Solve for k.

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