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Two cars are moving. The first car has twice the mass of the second car but only half as much kinetic energy. When both cars increase their speed by 3.41 m/s, they then have the same kinetic energy.

a) What is the original speed of the first car?

b)What is the original speed of the second car?

  • Physics -

    M1 = 2M2
    M1*V1^2 = (1/2)M2*V2^2 = (M1/4)V2^2
    V2 = 2 V1
    M1*(V1+3.41)^2 = M2*(V2+3.41)^2
    = (M1/2)*(2V1 +3.41)^2
    Cancel the M1's and solve this quadratic equation for V1:
    (V1 +3.41)^2 = (1/2)(2V1 + 3.41)^2

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