Posted by karina on Tuesday, February 8, 2011 at 10:33pm.
If you sketch this out you will have a right triangle, I will call ABC.
A is the vertex = angle of depression
AC (side b) = base = 1400 feet
BC (side a) = leg = 1100 feet
AB (side c) = hypotenuse = distance to landing site
To find angle A (angle of depression)
tan A = a/b = 1100/1400 = 0.7857
tan A = 0.7857
arctan 0.7857 = 38.16 deg
To find C (distance to airport)
c^2 = a^2 + b^2
c^2 = 1100^2 + 1400^2
c^2 = 1,210,000 + 1,960,000
c^2 = 3,170,000
c = 1780.45 feet
1780.45/5280 feet in mile = 0.34 miles
Related Questions
pre cal - Tamara is flying in a hot air balloon. The hot air balloon is flying ...
geometry - Hot air balloons require large amounts of both hot air and fabric ...
math - After flying at an altitude of 600 meters,a hot air balloon starts to ...
physics - a hot air balloon rise above the ground, accelerating upwards at a ...
physics - There are many ropes keeping a hot air balloon from floating away ...
physics - 1.A hot air balloon is rising upwards at a constant velocity of 5m.s ...
Physics - Hot air balloons float in the air because of the difference in density...
physics - The two hot air balloons in the drawing are 48.2 and h = 63.0 m above ...
Physical science - On a perfect day, you are hovering at low altitude in a hot-...
physics - On a perfect fall day, you are hovering at low altitude in a hot-air ...
For Further Reading