Posted by Nick on Tuesday, February 8, 2011 at 9:15pm.
Here is a worked example. Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html
Molar Mass of KCLO3 (potassium chlorate)= 39.10+35.45+3(16.00)=122.55
First use what you are given, then use the mole to mole ratio to cancel out moles KClO3 and multiply keeping mol O2.
(12.00 moles KClO3)x(3 mol O2/2 mol KClO3) =18 moles O2
:D
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