Posted by **Attalah** on Tuesday, February 8, 2011 at 7:12pm.

Solve each equation. Check for extraneous solutions.

Solve:|x+5|=3x-7

My answers were: x=6 and x=.5

I dont think they are right though, but I should get 2 answers right???....Help!

- Algebra II -
**helper**, Tuesday, February 8, 2011 at 7:24pm
6 is correct.

If you check your answers, you will find that .5 (1/2) is not a solution.

You must always check your answers in the original problem.

- Algebra II -
**Attalah**, Tuesday, February 8, 2011 at 7:25pm
So i wouldn't have 2 answers?

- Algebra II -
**helper**, Tuesday, February 8, 2011 at 7:40pm
One answer, x = 6.

.5 or 1/2 is an extraneous solution (not a valid solution).

If you are asked specifically if there are any extraneous solutions, then you would list it as such.

I've never had a problem ask for extraneous solutions, since it's not a solution to the problem.

- Algebra II -
**Attalah**, Tuesday, February 8, 2011 at 7:54pm
ok so would |2y-3|=3y-2 be y=-1??

- Algebra II -
**helper**, Tuesday, February 8, 2011 at 8:11pm
No, y = -1 is an extraneous solution.

y = 1, is the answer.

- Algebra II -
**Attalah**, Tuesday, February 8, 2011 at 8:13pm
|4w+3|-2=5

Would be: w= 5\4

- Algebra II -
**Attalah**, Tuesday, February 8, 2011 at 8:17pm
How would I solve:

2|z+1|-3=z-2

???

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