6 is correct.
If you check your answers, you will find that .5 (1/2) is not a solution.
You must always check your answers in the original problem.
So i wouldn't have 2 answers?
One answer, x = 6.
.5 or 1/2 is an extraneous solution (not a valid solution).
If you are asked specifically if there are any extraneous solutions, then you would list it as such.
I've never had a problem ask for extraneous solutions, since it's not a solution to the problem.
ok so would |2y-3|=3y-2 be y=-1??
No, y = -1 is an extraneous solution.
y = 1, is the answer.
Would be: w= 5\4
How would I solve:
algebra II - I'm quite clueless as to how to solve this. I know the quadratic ...
Algebra II - Please check answers: Use the equation of the exponential function ...
algebra - x/9 +3 = 8 - x/3 Solve?????? First, get rid of the fractions to make ...
algebra II - how would you solve this equation?? -4|7+d| = -44
algebra II - solve each equation. 5y-2(y+3)=4y
Algebra II - Solve the following equation for v: S = (-1/2)gt2 + vt
algebra II - Solve each a equation. 5x=-2x-6 -5y+7=-18
Honors Algebra II - Solve this equation. [2x 3 3z]=[5 3y 9]
college algebra II - using the quadratic equation solve: y^2+16+64=0
College Math II - x/x – 1 - 3/x = 1/2 I am not sure how to solve this equation ...