Posted by Attalah on Tuesday, February 8, 2011 at 7:12pm.
Solve each equation. Check for extraneous solutions.
Solve:x+5=3x7
My answers were: x=6 and x=.5
I don't think they are right though, but I should get 2 answers right???....Help!

Algebra II  helper, Tuesday, February 8, 2011 at 7:24pm
6 is correct.
If you check your answers, you will find that .5 (1/2) is not a solution.
You must always check your answers in the original problem.

Algebra II  Attalah, Tuesday, February 8, 2011 at 7:25pm
So i wouldn't have 2 answers?

Algebra II  helper, Tuesday, February 8, 2011 at 7:40pm
One answer, x = 6.
.5 or 1/2 is an extraneous solution (not a valid solution).
If you are asked specifically if there are any extraneous solutions, then you would list it as such.
I've never had a problem ask for extraneous solutions, since it's not a solution to the problem.

Algebra II  Attalah, Tuesday, February 8, 2011 at 7:54pm
ok so would 2y3=3y2 be y=1??

Algebra II  helper, Tuesday, February 8, 2011 at 8:11pm
No, y = 1 is an extraneous solution.
y = 1, is the answer.

Algebra II  Attalah, Tuesday, February 8, 2011 at 8:13pm
4w+32=5
Would be: w= 5\4

Algebra II  Attalah, Tuesday, February 8, 2011 at 8:17pm
How would I solve:
2z+13=z2
???
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