When you react hydrogen gas with nitrogen gas to form ammonia, How many grams of all species ( reactants and products) are left when you start with 140 grams of nitrogen and 40 grams of hydrogen?
duplicate post I think.
To determine the grams of all species (reactants and products) left when you start with 140 grams of nitrogen and 40 grams of hydrogen, we need to determine the limiting reactant. The limiting reactant is the reactant that is completely consumed in a reaction, which limits the amount of product that can be formed.
To find the limiting reactant, we need to compare the stoichiometric ratio between nitrogen and hydrogen in the balanced chemical equation for the reaction:
N2 + 3H2 -> 2NH3
The balanced equation tells us that 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3.
Step 1: Convert the given masses of nitrogen and hydrogen to moles.
140 grams of nitrogen * (1 mole / molar mass of nitrogen) = moles of nitrogen
40 grams of hydrogen * (1 mole / molar mass of hydrogen) = moles of hydrogen
Step 2: Determine the stoichiometric ratio of nitrogen to hydrogen.
moles of nitrogen / moles of hydrogen
Step 3: Compare the stoichiometric ratios to identify the limiting reactant.
If the stoichiometric ratio is 1:3 or higher, then hydrogen is the limiting reactant.
If the stoichiometric ratio is lower than 1:3, then nitrogen is the limiting reactant.
Step 4: Calculate the moles of NH3 produced from the limiting reactant.
moles of limiting reactant * (2 moles of NH3 / 1 mole of limiting reactant) = moles of NH3
Step 5: Calculate the mass of NH3 produced from the limiting reactant.
moles of NH3 * (molar mass of NH3 / 1 mole of NH3) = grams of NH3
Step 6: Determine the grams of unreacted nitrogen and hydrogen.
grams of reactant - grams of NH3 produced = grams of unreacted reactant
By following these steps, you can determine the grams of all species left when starting with 140 grams of nitrogen and 40 grams of hydrogen.