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April 16, 2014

April 16, 2014

Posted by **hannah** on Tuesday, February 8, 2011 at 12:42pm.

- math -
**MathMate**, Tuesday, February 8, 2011 at 5:16pmcsc(θ)=-5/3

1/sin(θ)=-5/3

sin(θ)=1/(-5/3)=-3/5

cos(θ)=-√(1-(-3/5)²)

=-4/5

tan(θ)=sin(θ)/cos(θ)

=(-3/5)/(-4/5)

=3/4

tan(2θ)=2tan(&theta))/(1-tan²(θ))

=2(3/4)/(1-(3/4)²)

=3.43

(note: 2θ is in the first quadrant.

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