Posted by **Leanna** on Monday, February 7, 2011 at 10:53pm.

Let f be a twice-differentiable function such that f(2)=5 and f(5)=2. Let g be the function given by g(x)= f(f(x)).

(a) Explain why there must be a value c for 2 < c < 5 such that f'(c) = -1.

(b) Show that g' (2) = g' (5). Use this result to explain why there must be a value k for 2 < k < 5 such that g"(k)= 0.

(c) Show that if f"(x) = 0 for all x, then the graph of g does not have a point of inflection.

(d) Let h(x) = f(x) - x. Explain why there must be a value r for 2 < r < 5 such that h(r) = 0.

I know you have to use the intermediate value theorem and mean value theorem but don't know how.

- Calculus -
**MathMate**, Monday, February 7, 2011 at 11:26pm
a. use the mean-value theorem

f(2)=5 and f(5)=2

=> (f(5)-f(2))/(5-2)=(2-5)/(5-2)=-1

It is a straight application of the mean-value theorem to state that there exists 2<c<5 such that f'(c)=(f(5)-f(2))/(5-2).

b. Use the chain rule to differentiate g(x) to get

g'(x)=f'(x)*f'(f(x))

So

g'(2)=f'(2)*f'(f(2))=f'(2)*f'(5)

g'(5)=f'(5)*f'(f(5))=f'(5)*f'(2)

Therefore g'(2)=g'(5)

c. If f"(x)=0 ∀x, then

f(x)=mx+b, m,b∈ℝ.

f'(x)=m

g'(x)=m*m(f(x))=m² (m is not dependent on x)

=> g"(x)=0

d. h(x)=f(x)-x

=> h(2)=f(2)-2=5-2=3

and

=> h(5)=f(5)-5=2-5=-3

Since f(x) is continuous and differentiable in (2,5), h(x) is also continuous and differentiable. Since h(r)=0 lies between h(2) and h(5) so the intermediate value theorem applies directly to state that 2<r<5 exists such that h(r)=0.

Post if you need more details.

## Answer This Question

## Related Questions

- calculus (hint?) - f(x) is a twice differentiable function such that f(2x)=f(x+5...
- calculus - a) Obtain all solutions of the equation z^3 +1 = 0 b) Let z = x + iy...
- AP CALC - 1. Let f be a twice-differentiable function such that f (2) = 8 and f...
- Functions - math - The function f is such that f(x) = 2x + 3 for x ? 0. The ...
- Calculus - Let f be a one-to-one function whose inverse function is given by the...
- Math - Is the step function differentiable in its domain? I answered it and said...
- Last two CALC questions. :) - 8. If f(x) = sin(7 − 5x), find f′(&#...
- Calculus - Let f be a differentiable function defined on the closed interval [a,...
- calculus - Let f(x) = (x+1)/(x-1). Show that there are no vlue of c such that f(...
- Calculus - If f is a function such that [(f(b)-f(a))/(b-a)]=2 , then which of ...

More Related Questions