# math

posted by .

4|3-2x6|-3^2
can you tell me how to solve? please

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Is 2x6 supposed to be 2 x^6?
What gets squared at the end? The -3 exponent?

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4|3 - 2x^6| - 3^2 = ?

I think you must have copied this wrong.

This problem, as typed, is not easy to solve.

I used an online calculator and there are 12 different roots for x (4 real and 10 complex.

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no its just how i put it. yes

• multiple posts -

angiie,
Please refrain from multiple posts. The time for teachers to read multiple posts or to determine if they are multiple posts could very well be used for answering questions.

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MathMate
sorry i didn't know it did that. my commputer was taking a while to load and i clicked a few times before i let it load. sorry agaiin

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to drwls
My equation was just how i put it. 2x6 is not supposed to be 2 x^6. its just 2x6.
And the -3 exponent yes it gets squared at the end.

what dose these lines mean | | squareroot?

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Assuming you mean:
4|3-2x^6|-3²=0

Then
4|3-2x^6|=3²
|3-2x^6|=9/4
There are two cases,
a. when 3-2x^6 >0
|3-2x^6|=9/4
=> 3-2x^6=9/4
=> 2x^6=3-9/4=3/4
=> x^6=3/8
=> x=±(3/8)^(1/6) (x∈ℝ, i.e. x is real)

b. when 3-2x^6<0
|3-2x^6|=9/4
=> -(3-2x^6)=9/4
=> 2x^6=9/4+3=21/4
=> x^6=21/8
=> x=±(21/8)^(1/6) (x∈ℝ)

As Helper said, there are 2*4 complex roots which we do not consider in the real domain.

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If there is no x, then you don't have a variable!