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Posted by on Monday, February 7, 2011 at 10:16pm.

A moving electron passes near the nucleus of a gold atom, which contains 79 protons and 118 neutrons. At a particular moment the electron is a distance of 7.5 × 10−9 m from the gold nucleus.

What is the magnitude of the force exerted by the gold nucleus on the electron?

  • physics - , Tuesday, February 8, 2011 at 8:27am

    I seem to recall answering this already.

    F = k*Q1*Q2/R^2 = 79k*e^2/R^2

    (Coulomb's law; k = Coulomb's constant)

    Get to know it

  • physics - , Saturday, February 12, 2011 at 9:01pm

    I'm not getting the answer using this formula. Can you explain it a little more. Thanks

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