A moving electron passes near the nucleus of a gold atom, which contains 79 protons and 118 neutrons. At a particular moment the electron is a distance of 7.5 × 10−9 m from the gold nucleus.
What is the magnitude of the force exerted by the gold nucleus on the electron?
physics - drwls, Tuesday, February 8, 2011 at 8:27am
I seem to recall answering this already.
F = k*Q1*Q2/R^2 = 79k*e^2/R^2
(Coulomb's law; k = Coulomb's constant)
Get to know it
physics - apm, Saturday, February 12, 2011 at 9:01pm
I'm not getting the answer using this formula. Can you explain it a little more. Thanks